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Wave Optics

Question
CBSEENPH12039975

The mass of a Li presubscript 3 presuperscript 7 nucleus is 0.042u less than the sum of the masses of all its nucleons. The binding energy per nucleon is Li presubscript 3 presuperscript 7 nucleus is nearly

  • 46 MeV

  • 5.6 MeV

  • 3.9 MeV

  • 23 MeV

Solution

B.

5.6 MeV

If, m = 1 u, c= 3 x 108 ms-1, then 
E = 931 MeV i.e. 1 u = 931 MeV
Binding energy = 0.042 x 931 = 39.10 MeV
therefore, Binding energy per nucleon
= 39.10/7 = 5.58 = 5.6 MeV

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