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Wave Optics

Question
CBSEENPH12039947
Wired Faculty App

The input signal given to a CE amplifier having a voltage gain of 150 is straight V subscript straight i space equals space open parentheses 15 space straight t space plus space fraction numerator 2 straight pi over denominator 3 end fraction close parentheses The corresponding output signal will be

  • 300 space cos space open parentheses 15 space straight t space plus straight pi over 3 close parentheses
  • 75 space cos space open parentheses 15 space straight t space plus fraction numerator 2 straight pi over denominator 3 end fraction close parentheses
  • 2 space cos space open parentheses 15 space straight t space plus fraction numerator 5 straight pi over denominator 3 end fraction close parentheses
  • 300 space cos space open parentheses 15 space straight t space plus fraction numerator 4 straight pi over denominator 3 end fraction close parentheses

Solution

D.

300 space cos space open parentheses 15 space straight t space plus fraction numerator 4 straight pi over denominator 3 end fraction close parentheses

Input signal of a CE amplifier,

straight V subscript in space equals space 2 space cos space open parentheses 15 space straight t space plus space straight pi over 3 close parentheses Voltage space gain space straight A subscript straight v space equals space 150 As space CE thin space amplifier space gives space phase space difference space of space straight pi between space input space and space output space signals So comma straight A subscript straight v space equals space fraction numerator straight V subscript straight o over denominator straight V subscript in space end fraction space rightwards double arrow space straight V subscript straight o space equals straight A subscript straight v straight V subscript in straight V subscript straight o space equals space 150 space straight x space 2 space cos space open parentheses 15 space straight t space plus straight pi over 3 space plus straight pi close parentheses straight V space equals space 300 space cos space open parentheses 15 space straight t space plus fraction numerator 4 straight pi over denominator 3 end fraction close parentheses

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