A biconvex lens has a radius of curvature of magnitude 20 cm. Which one of the following options describes best the image formed on an object of height 2 cm placed 30 cm from the lens?

Virtual, upright, height = 0.5 cm

Real, invented, height = 4 cm

Real, inverted, height = 1 cm

Virtual, upright, height = 1 cm

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Solution

Real, invented, height = 4 cm

In space general space we space have space assumed space straight mu space equals space 1.5 So comma space straight f space equals space 20 space cm 1 over straight f space equals space 1 over straight v space plus 1 over straight u 1 over 20 space equals space 1 over straight v space plus 1 over 30 1 over straight v space equals space 1 over 20 minus 1 over 30 space equals space 10 over 600 straight v equals space 60 space cm fraction numerator straight h subscript straight i over denominator straight h subscript straight o space end fraction space equals space 2 straight h subscript straight i space equals space 2 space straight x space vertical line straight h subscript straight o vertical line straight h subscript straight i space equals space 4 space cm

Here, image is real, inverted, magnified field and height of image is 4 cm

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