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Wave Optics

Question
CBSEENPH12039899

A certain mass of hydrogen is changed to helium the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u =931 MeV)

  • 2.67 MeV

  • 26.7 MeV

  • 6.675 MeV

  • 13.35 MeV

Solution

C.

6.675 MeV

Here comma space increment straight m equals 0.02866 space straight U
therefore comma
Energy space liberated
equals space fraction numerator 0.02866 space straight x space 931 over denominator 4 end fraction space equals space fraction numerator 26.7 over denominator 4 end fraction space MeV space equals space 6.675 space MeV