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Wave Optics

Question
CBSEENPH12039897

The wavelength λe of an electron and λp of a photon of same energy E are related by

  • straight lambda subscript straight p proportional to space straight lambda subscript straight e superscript 2
  • straight lambda subscript straight p proportional to space straight lambda subscript straight e
  • straight lambda subscript straight p proportional to square root of space straight lambda subscript straight e end root
  • straight lambda subscript straight p proportional to space fraction numerator 1 over denominator square root of straight lambda subscript straight e end root end fraction

Solution

A.

straight lambda subscript straight p proportional to space straight lambda subscript straight e superscript 2 Wavelength space of space electron comma
straight lambda subscript straight e space equals space fraction numerator straight h over denominator square root of 2 mE end root end fraction
and space proton space straight lambda subscript straight p space equals space hc over straight E
rightwards double arrow space straight lambda subscript straight e superscript 2 space equals space fraction numerator straight h squared over denominator 2 mE end fraction space or space space straight E space equals space hc over straight lambda subscript straight p
therefore space space straight lambda subscript straight e superscript 2 space equals space fraction numerator straight h squared over denominator 2 straight m space hc over straight lambda subscript straight p end fraction space
rightwards double arrow space space straight lambda subscript straight e superscript 2 space equals space fraction numerator straight h squared over denominator 2 mhc end fraction straight lambda subscript straight p
straight lambda subscript straight e superscript 2 space proportional to straight lambda subscript straight p