Question

If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is,

25

75

60

50

Solution

For de-Broglie wavelength,
$straight lambda subscript 1 space equals space straight h over straight p equals fraction numerator straight h over denominator square root of 2 mK end root end fraction space$ ... (i)
$straight lambda subscript 2 space equals space fraction numerator straight h over denominator square root of 2 straight m 16 space straight K end root end fraction space space space space space equals space fraction numerator straight h over denominator 4 square root of 2 mK end root end fraction space space space space equals space straight lambda subscript 1 over 4$ ... (ii)
From equations (i) and (ii),
$straight lambda subscript 2 space equals space 25 percent sign space of space straight lambda subscript 1$
There is 75% change in the wavelength.

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Wave Optics

If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is,

25

75

60

50

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For Daily Free Study Material Join wiredfaculty

Wave Optics

If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is, 25 75 60 50

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is,

25

75

60

50