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Wave Optics

Question
CBSEENPH12039881

When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased from 0.5 eV to 0.8 eV. The work function of the metal is,

  • 0.65 eV

  • 1.0 eV

  • 1.3 eV

  • 1.5 eV

Solution

B.

1.0 eV

For photoelectric equation,
(KE)minhν space minus space straight ϕ subscript straight o
For the first condition,
0.5 = E - straight ϕ subscript straight o                ... (i)
For the second condition,
0.8 space equals space 1.2 space straight E space minus space straight ϕ subscript straight o      ... (ii)
From equations (i) and (ii),
0.5 space equals space straight E space minus space straight ϕ subscript straight o and 
0.8 space equals space 1.2 space straight E space minus space straight ϕ subscript straight o
-0.3 = -0.2 E
E = fraction numerator 0.3 over denominator 0.2 end fraction equals 1.5 space e V
From expression (i),
0.5 = 1.5 - straight ϕ subscript straight o
rightwards double arrow space straight ϕ subscript straight o space equals space 0.5 space minus 0.5 space
space space space space space space space space space space equals space 1 space eV

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