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Electrostatic Potential And Capacitance

Question
CBSEENPH12039873

A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are: 

  • 300 V, 15 A

  • 450 V, 15 A

  • 450 V, 13.5 A

  • 600 V, 15 A

Solution

B.

450 V, 15 A

Initial power = 3000 W
As the efficiency is 90%, then final power = 3000 space x 90 over 100 = 2700 W
That is,

space space space space space straight V subscript 1 straight I subscript 1 space equals space 3000 space straight W
rightwards double arrow space straight V subscript 1 straight I subscript 1 space equals space 2700 space straight W space        ... (i)
So, straight V subscript 2 space equals space fraction numerator 2700 over denominator 6 space end fraction space equals space 900 over 2 space equals space 450 space straight V
straight I subscript 1 space equals space 3000 over 200 space equals space 15 space straight A

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