Question
In an ammeter 0.2 % of the main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be,
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1/499 G
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499/500 G
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1/500 G
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500/499 G
Solution
A.
1/499 G
For ammeter,
0.0002 I x G = 0.998 I x rg
rg =
That is,
Resistance of ammeter is approximately equal to resistance of shunt rB.