Question
If voltage across a bulb rated 220 V -100W drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is
-
20%
-
2.5%
-
5%
-
10%
Solution
C.
5%
Power P= V2/R
For small variation
ΔP/P x 100%
Therefore, power would decrease by 5%