-->

Electrostatic Potential And Capacitance

Question
CBSEENPH12039861

If voltage across a bulb rated 220 V -100W drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is

  • 20%

  • 2.5%

  • 5%

  • 10%

Solution

C.

5%

Power P= V2/R
For small variation 
ΔP/P x 100% 
fraction numerator 2 space straight x space ΔV over denominator straight V end fraction space x space 100 percent sign
space equals space 2 space x space 2.5 space equals space 5 percent sign
Therefore, power would decrease by 5%

Some More Questions From Electrostatic Potential and Capacitance Chapter