Question
A mixture consists of two radioactive materials A1 and A2 with half-lives of 20 s and 10 s respectively. Initially, the mixture has 40 g of A1 and 160 g of A2. The amount of the two in the mixture will become equal after
-
60 s
-
80 s
-
20 s
-
40 s
Solution
D.
40 s
For 40 g amount
So, after 40 A1 and A2 remains same.