+91-8076753736[email protected]
logo
logo
-->

Wave Optics

Question
CBSEENPH12039839
Wired Faculty App

In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2kΩ is 2V. If the base resistance is 1kΩ and the current amplification of the transistor is 100, the input signal voltage is

  • 0.1 V

  • 1.0 V

  • 1 mV

  • 10 mV

Solution

D.

10 mV

Current amplification factor
straight beta space equals space fraction numerator increment straight l subscript straight C over denominator increment straight I subscript straight B end fraction Collector space resistance increment straight l subscript straight C space equals space fraction numerator 2 space straight V over denominator space 2 space straight x space 10 cubed straight capital omega end fraction space equals space 1 space straight x space 10 to the power of negative 3 end exponent space straight A Base space current increment straight I subscript straight B space equals space fraction numerator straight V subscript straight B over denominator straight R subscript straight B space end fraction space equals fraction numerator straight V subscript straight B over denominator 1 space straight x space 10 cubed end fraction space equals space straight V subscript straight B space straight x space 10 to the power of negative 3 end exponent Given comma space straight beta space equals space 100 Now comma space 100 space equals space fraction numerator 10 to the power of negative 3 end exponent over denominator straight V subscript straight B space straight x 10 to the power of negative 3 end exponent end fraction straight V subscript straight B space equals space 1 over 100 straight V space equals space 10 mV

Some More Questions From Wave Optics Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation