For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index

Lies between $square root of 2 space and space 1$

Lies between 2 and $square root of 2$

is less than 1

is greater than 2

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Solution

Lies between 2 and $square root of 2$

straight mu space equals space fraction numerator open parentheses begin display style fraction numerator straight A space plus δm over denominator 2 end fraction end style close parentheses over denominator Sin space straight A divided by 2 end fraction equals fraction numerator open parentheses begin display style fraction numerator straight A space plus straight A over denominator 2 end fraction end style close parentheses over denominator Sin space straight A divided by 2 end fraction

In given situation value of A varies from 0 to 90^o. so,

straight mu subscript min space equals space 2 space cos 90 to the power of straight o over 2 space equals space square root of 2 and space straight u subscript max space equals space 2 space cos 0 to the power of straight o space equals 2

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