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Current Electricity

Question
CBSEENPH12039823
Wired Faculty App

The power dissipated in the circuit shiwn in the figure is 30 Watt. The value of R is

  • 20 Ω

  • 15Ω

  • 10Ω

  • 5Ω

Solution

C.

10Ω

Here, 
R1 = R2= ?
R2 = 5Ω, V = 10 V
and P= 30 W
Hence,
straight P equals straight V squared over straight R subscript 1 plus straight V squared over straight R subscript 2 10 squared over straight R space equals space 30 minus 10 squared over 5 100 over straight R space equals space 30 minus 20 straight R space equals space 10 straight capital omega

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