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Wave Optics

Question
CBSEENPH12039820

The angle of incidence for a ray of light at a refracting surface of a prism is 45o. The angle of prism is 60o. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are

  • 30osquare root of 2

  • 45osquare root of 2

  • 30ofraction numerator 1 over denominator square root of 2 end fraction

  • 45ofraction numerator 1 over denominator square root of 2 end fraction

Solution

A.

30osquare root of 2

Consider a ray of light PQ incident on the surface AB and moves along RS, after passing through the prism ABC.

Given that, incident ray suffers minimum deviation. therefore, the ray inside the prism must be parallel to the base BC of the prism.
From the geometry of the prism and the ray diagram, it is evident that
Angle of incidence, i = 45o
Angle of refraction, r = r' = 30o
Angle of emergence, e = 45o

Therefore, minimum deviation suffered by the ray is,
straight delta subscript min space equals space left parenthesis straight i plus straight e right parenthesis space minus space left parenthesis straight r plus straight r apostrophe right parenthesis
space space space space space space space space equals space 90 to the power of straight o space minus space 60 to the power of straight o space
space space space space space space space space space equals space 30 to the power of straight o

Also, using the formula,
straight mu space equals space fraction numerator sin space open parentheses begin display style fraction numerator straight A plus straight delta subscript straight m over denominator 2 end fraction end style close parentheses over denominator sin space straight A divided by 2 end fraction
where, straight mu is the refractive index of the material of the prism.
A = Angle of prism = 60o
Therefore,
straight mu space equals space fraction numerator sin space open parentheses begin display style fraction numerator 60 to the power of straight o plus 30 to the power of straight o over denominator 2 end fraction end style close parentheses over denominator sin space begin display style 60 to the power of straight o over 2 end style end fraction

space space space equals space fraction numerator sin space 45 to the power of straight o over denominator sin space 30 to the power of straight o end fraction

space space equals space fraction numerator begin display style bevelled fraction numerator 1 over denominator square root of 2 end fraction end style over denominator 1 divided by 2 end fraction

space space equals fraction numerator 2 over denominator square root of 2 end fraction

space space equals space square root of 2

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