-->

Electrostatic Potential And Capacitance

Question
CBSEENPH12039797

A parallel plate air capacitor of capacitance C is connected to a cell of emf V and then disconnected from it. A dielectric slab of a dielectric slab of dielectric constant K, which can just fill the air gap of the capacitor, is now inserted in it. which of the following is incorrect?

  • The potential difference between the plates decreases K times

  • The energy stored in the capacitor decreases K times

  • The change in energy stored is 1 half C V squared space open parentheses 1 over K minus 1 close parentheses

  • The charge on the capacitor is not conserved

Solution

C.

The change in energy stored is 1 half C V squared space open parentheses 1 over K minus 1 close parentheses

When space straight a space parallel space plate space air space capacitor space connected space to space cell space of space emf space straight V comma space
then space charge space stored space will space be
straight q space equals space CV
rightwards double arrow straight V space equals space straight q over straight C
Also space energy space stored space is space straight U space equals 1 half CV squared space equals fraction numerator straight q squared over denominator 2 straight C end fraction
As the battery is disconnected from the capacitor the charge will not be destroyed i.e. q' = q with the introduction of dielectric in the gap of capacitor the new capacitance will be
C' = CK
rightwards double arrow space space space space space straight V apostrophe space equals space fraction numerator straight q over denominator straight C apostrophe end fraction space equals space straight q over straight C
The space new space energy space stored space will space be space
straight U to the power of apostrophe space equals space fraction numerator straight q squared over denominator 2 CK end fraction
increment straight U space equals space straight U to the power of apostrophe minus straight U space equals space fraction numerator straight q squared over denominator 2 straight C end fraction open parentheses 1 over straight K minus 1 close parentheses
space equals space 1 half CV squared space open parentheses 1 over straight K minus 1 close parentheses

Some More Questions From Electrostatic Potential and Capacitance Chapter