Question
A p-n-p transistor is connected in a common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be,
-
3.69,3.84
-
4,4
-
4,3.69
-
4, 3.84
Solution
D.
4, 3.84
Given,
Resistance across load, RL = 800 ohm
Voltage drop across load, VL = 0.8 V
Input resistance of the circuit, Ri = 192 ohm
Collector current is given by,
Therefore, Current amplification = 
Voltage gain, AV is,
Power gain,
AP = 
= (0.96)2 x 
AP = 3.84
