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Wave Optics

Question
CBSEENPH12039787

A siren emitting a sound of frequency 800 Hz moves away from an observer towards a cliff at a speed of 15 m/s. Then, the frequency of sound that the observer hears in the echo reflected from the cliff is (Take, velocity of sound in air = 330 m/s)

  • 800 Hz

  • 838 Hz

  • 885 Hz

  • 765 Hz

Solution

B.

838 Hz

The situation can be illustrated as follows:

Frequency of sound that the observer hear in the echo reflected from the cliff is given by,
f' = open parentheses fraction numerator straight v over denominator straight v minus straight v subscript straight s end fraction close parentheses
where,
f = original frequency of source
v= velocity of the sound
vs = velocity of the source
So, straight f apostrophe space equals space open parentheses fraction numerator 330 over denominator 330 minus 15 end fraction close parentheses 800 space equals space 838 space Hz

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