Question
A long solenoid has 1000 turns. when a current of 4 A flows through it, the magnetic flux linked with each turn of the solenoid is 4x10-3 Wb. The self inductance of the solenoid is,
-
3H
-
2H
-
1H
-
4H
Solution
C.
1H
Given,
Number of turns in the solenoid, N= 1000
Current, I = 4 A
Magnetic flux, = 4 x 10-3 Wb
Self-inductance of solenoid is given by, ... (i)
Putting the value of equation in (i), we get
L =
= 1 H