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Wave Optics

Question
CBSEENPH12039783

Given the value of rydberg constant is 10 m-1, the wave number of the last line of the Balmer series in hydrogen spectrum will be:

  • 0.5 x 107 m-1

  • 0.25 x 107 m-1

  • 2.5 x10m-1

  • 0.025 x 104 m-1

Solution

B.

0.25 x 107 m-1

Rydberg constant, r = 107 m-1
For last line in Balmer series,


n2infinity; n1 = 2
We know,
space space space space 1 over straight lambda equals space R open parentheses 1 over n subscript 1 squared minus 1 over n subscript 2 squared close parentheses
rightwards double arrow space 1 over straight lambda equals italic 10 to the power of italic 7 open parentheses 1 over 2 squared minus 1 over italic infinity close parentheses
italic rightwards double arrow italic space nu with italic bar on top italic space italic equals italic space italic 1 over lambda italic equals italic 10 to the power of italic 7 over italic 4
italic space italic space italic space italic space italic space italic space italic space italic space italic space italic equals italic 0 italic. italic 25 italic space x italic space italic 10 to the power of italic 7 italic space m to the power of italic minus italic 1 end exponent