Question
The intensity at the maximum in a Young's double slit experiment is Io. Distance between two slits is d = 
, where 
is the wavelength of light used in the experiment. What will be the intensity infront of one of the slits on the screen placed at a distance D = 10 d?
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3
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Io
Solution
C.
In the fig., S1 and S2 are the two different slits.
Given, distances between slits S1 and S2
d = 5
Distance between the screen and slits, D = 10 d = 50 
is the wavelength of the light used in the experiment.
In Young's double slit experiment, the maximum intensity is Io.
Path difference,
Path difference of
corresponds to phase difference 2
.
So, for path difference
, phase difference is
We know,
I = Io cos2
is the wavelength of the light used in the experiment.In Young's double slit experiment, the maximum intensity is Io.
Path difference,
Path difference of
corresponds to phase difference 2.So, for path difference
, phase difference isWe know,
I = Io cos2
