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Current Electricity

Question
CBSEENPH12039753

In an a.c. circuit, the instantaneous e.m.f. and current are given by
e = 100 sin 30 t

i = 20 sin 30 t -π4

In one cycle of a.c., the average power consumed by the circuit and the wattless current are, respectively

  • 50,0

  • 50,10

  • 10002, 10

  • 502,0

Solution

C.

10002, 10

Pavg = Vrms Irms cos θ= V02I02cos θ = 1002202 cos 45o = 10002wattWattless current = Irms sin θ= I02sin θ= 202 sin 450= 10 amp

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