Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10Ω. The internal resistance of the two batteries are 1Ω and 2Ω respectively. The voltage across the load lies between :

11.7 V and 11.8 V

11.6 V and 11.7 V

11.5 V and 11.6 V

11.4 V and 11.5 V

Solution

11.5 V and 11.6 V

$\frac{V - 12}{1} + \frac{V - 13}{2} + \frac{V - 0}{10} = 0 [L e t p o t e n t i a l a t P, Q, U = 0 a n d a t R = V \Rightarrow \frac{V}{1} + \frac{V}{2} + \frac{V}{10} = \frac{12}{1} + \frac{13}{2} + \frac{0}{10} \Rightarrow \frac{10 + 5 + 1}{10} V = \frac{24 + 13}{2} \Rightarrow V (\frac{16}{10}) = \frac{37}{2} \Rightarrow V = \frac{37 x 10}{16 x 2} = \frac{370}{32} = 11.56 v o l t$ Using Kirchhoff's law at P we get

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Current Electricity

Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10Ω. The internal resistance of the two batteries are 1Ω and 2Ω respectively. The voltage across the load lies between :

11.7 V and 11.8 V

11.6 V and 11.7 V

11.5 V and 11.6 V

11.4 V and 11.5 V

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For Daily Free Study Material Join wiredfaculty

Current Electricity

Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10Ω. The internal resistance of the two batteries are 1Ω and 2Ω respectively. The voltage across the load lies between : 11.7 V and 11.8 V 11.6 V and 11.7 V 11.5 V and 11.6 V 11.4 V and 11.5 V

Some More Questions From Current Electricity Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10Ω. The internal resistance of the two batteries are 1Ω and 2Ω respectively. The voltage across the load lies between :

11.7 V and 11.8 V

11.6 V and 11.7 V

11.5 V and 11.6 V

11.4 V and 11.5 V