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Nuclei

Question
CBSEENPH12039738
Wired Faculty App

The binding energy per nucleon of deuteron (21H) and helium nucleus (42He) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

  • 13.9 MeV

  • 26.9 MeV

  • 23.6 MeV

  • 19.2 MeV

Solution

C.

23.6 MeV

As given,straight H presubscript 1 superscript 2 space plus space straight H presubscript 1 superscript 2 space rightwards arrow for space of space subscript 2 He to the power of 4 space plus space energy
The binding energy per nucleon of a deuteron (1H2 ) = 1.1 MeV
∴ Total binding energy = 2× 1.1 = 2.2 MeV
The binding energy per nucleon of helium (2He4 ) = 7 MeV
∴ Total binding energy = 4× 7 = 28 MeV
Hence, energy released in the above process = 28 - 2× 2.2 = 28 - 4.4 = 23.6 MeV

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