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Electric Charges And Fields

Question
CBSEENPH12039714

A charged particle q is shot towards another charged particle Q which is fixed, with a speed v it approaches Q upto a closest distance r and then returns. If q were given a speed 2v, the closest distances of approach would be

  • r

  • 2r

  • r/2

  • r/4

Solution

D.

r/4

By principle of conservation of energy
1 half mv squared space equals space kqQ over straight r space..... space left parenthesis straight i right parenthesis

Finally comma space 1 half space straight m left parenthesis 2 straight v right parenthesis squared space equals space fraction numerator begin display style KqQ end style over denominator straight r squared end fraction space... left parenthesis ii right parenthesis
Equation space left parenthesis straight i right parenthesis divided by left parenthesis ii right parenthesis
1 fourth space equals space fraction numerator straight r apostrophe over denominator straight r end fraction
rightwards double arrow space straight r apostrophe space equals space fraction numerator begin display style straight r end style over denominator 4 end fraction