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Nuclei

Question

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If radius of $Al presubscript 13 presuperscript 27$ nucleus is estimated to be 3.6 Fermi then the radius $Te presubscript 52 presuperscript 125$ nucleus

6 fermi

8 fermi

4 fermi

5 fermi

Solution

A.

6 fermi

fraction numerator straight R over denominator 3.6 end fraction space equals space open parentheses 125 over 27 close parentheses to the power of 1 third end exponent rightwards double arrow space straight R space equals space 6 space fermi

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