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Nuclei

Question
CBSEENPH12039671

The intensity of gamma radiation from a given source is I. On passing through 36 mm of lead, it is reduced to l/8. The thickness of lead which will reduce the intensity to l/2 will be

  • 6 mm

  • 9 mm

  • 18 mm

  • 12 mm

Solution

D.

12 mm

straight I apostrophe space equals le to the power of negative μk end exponent
rightwards double arrow space straight x equals 1 over straight mu log subscript straight e space fraction numerator straight I over denominator straight I divided by 8 end fraction space equals 3 over straight mu log subscript straight e 2 space.... left parenthesis straight i right parenthesis
straight x equals straight I over straight mu log subscript straight e space fraction numerator straight I over denominator straight I divided by 2 end fraction equals straight I over straight mu log subscript straight e 2 space..... left parenthesis ii right parenthesis
From space equation space left parenthesis straight I right parenthesis space and space left parenthesis ii right parenthesis comma space straight x equals space 12 space mm