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Current Electricity

Question
CBSEENPH12039668

An inductor (L = 100 mH), a resistor (R = 100 Ω) and a battery (E = 100 V) are initially connected in series as shown in the figure. After a long time the battery is disconnected after short-circuiting the points A and B. The current in the circuit 1 mm after the circuit is

  • 1 A

  • 1/e A

  • e A

  • 0.1 A

Solution

B.

1/e A

straight I space equals space straight I subscript 0 straight e to the power of negative Rt divided by straight L end exponent
space equals space 1 over straight e straight A