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Nuclei

Question
CBSEENPH12039662

If the binding energy per nucleon in Li presubscript 3 presuperscript 7and He presubscript 4 presuperscript 2 nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction

straight p space plus space Li presubscript 3 presuperscript 7 space rightwards arrow with space on top space 2 space He presubscript 2 presuperscript 4
energy of proton must be

  • 39.2 MeV

  • 28.24 MeV

  • 17.28 MeV

  • 1.46 MeV

Solution

C.

17.28 MeV

EP = (8 × 7.06 – 7 × 5.60) MeV
= 17.28 MeV