Question
The resistance of a bulb filament is 100 Ω at a temperature of 100°C. If its temperature coefficient of resistance be 0.005 per °C, its resistance will become 200 Ω at a temperature of
-
200°C
-
300°C
-
400°C
-
500°C
Solution
B.
300°C
200 = 100[1 +(0.005 × ∆t)]
T− 100 = 200
T = 300° C
