-->

Current Electricity

Question
CBSEENPH12039643

In a Wheatstone’s bridge, there resistances P, Q and R connected in the three arms and the fourth arm is formed by two resistances S1 and S2 connected in parallel. The condition for bridge to be balanced will be

  • straight P over straight Q space equals space fraction numerator straight R space left parenthesis straight S subscript 1 plus straight S subscript 2 right parenthesis over denominator straight S subscript 1 straight S subscript 2 end fraction
  • straight P over straight Q space equals space fraction numerator straight R over denominator straight S subscript 1 plus straight S subscript 2 end fraction
  • straight P over straight Q space equals space fraction numerator 2 straight R over denominator straight S subscript 1 plus straight S subscript 2 end fraction
  • straight P over straight Q space equals space fraction numerator straight R left parenthesis straight S subscript 1 plus straight S subscript 2 right parenthesis over denominator 2 straight S subscript 1 straight S subscript 2 end fraction

Solution

A.

straight P over straight Q space equals space fraction numerator straight R space left parenthesis straight S subscript 1 plus straight S subscript 2 right parenthesis over denominator straight S subscript 1 straight S subscript 2 end fraction

Some More Questions From Current Electricity Chapter