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Wave Optics

Question
CBSEENPH12039528

Assume that a neutron breaks into a proton and an electron. The energy released during this process is(Mass of neutron = 1.6725 x 10–27kg; mass of proton = 1.6725 x 10–27kg; mass of electron = 9 x 10–31kg)

  • 0.73 MeV

  • 7.10 MeV

  • 6.30 MeV

  • 5.4 MeV

Solution

A.

0.73 MeV

increment straight m space equals space left parenthesis straight m subscript straight p plus straight m subscript straight e right parenthesis minus straight m subscript straight n
space equals space 9 space straight x 10 to the power of negative 31 end exponent space kg.
Energy space released space equals space left parenthesis 9 space straight x space 10 to the power of negative 31 end exponent space kg right parenthesis space straight c squared space joules
space equals space fraction numerator 9 space straight x 10 to the power of negative 31 end exponent space straight x space left parenthesis 3 space straight x space 10 to the power of 8 right parenthesis squared over denominator 1.6 space straight x space 110 to the power of negative 13 end exponent end fraction space space MeV
space equals space 0.73 space MeV

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