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Electric Charges And Fields

Question
CBSEENPH12039521

Two charges, each equal to q, are kept at x = −a and x = a on the x-axis. A particle of mass m and charge qo =-q/2 is placed at the origin. If charge qo is given a small displacement (y<< a) along the y-axis, the net force acting on the particle is proportional to

  • y

  • -y

  • 1/y

  • -1/y

Solution

A.

y



Net force in negative y -direction,
Fnet = 2F cos θ 
straight F subscript net space equals space fraction numerator 2 kq open parentheses begin display style straight q over 2 end style close parentheses over denominator left parenthesis square root of straight y squared plus straight a squared end root right parenthesis to the power of 3 divided by 2 end exponent end fraction
rightwards double arrow space straight F subscript net space equals space fraction numerator kq squared straight y over denominator straight a cubed end fraction
rightwards double arrow space straight F subscript net space proportional to space straight y