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Wave Optics

Question
CBSEENPH12039519

In a hydrogen like atom, electron makes the transition from an energy level with quantum number n to another with a quantum number (n – 1). If n >> 1, the frequency of radiation emitted is proportional to 

  • 1/n

  • 1/n2

  • 1/n3/2

  • 1/n3

Solution

D.

1/n3

An energy gap, ΔE = hv
Here, h is Planck's constant
therefore,
Frequency
straight v space equals space fraction numerator increment straight E over denominator straight h end fraction space equals space straight k space open square brackets fraction numerator 1 over denominator left parenthesis straight n minus 1 right parenthesis squared end fraction minus 1 over straight n squared close square brackets
rightwards double arrow space straight v space equals fraction numerator straight k 2 straight n over denominator straight n squared left parenthesis straight n minus 1 right parenthesis squared end fraction space
straight v space proportional to 1 over straight n cubed