Question
In an LCR circuit as shown below both switches are open initially. Now switch S1 is closed, S2 kept open. (q is charge on the capacitor and τ = RC is capacitive time constant). Which of the following statement is correct?
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Work done by the battery is half of the energy dissipated in the resistor
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At t = τ, q = CV/2
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At t = 2τ, q = CV (1-e-2)
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At t = τ/2, q = CV (1-e-1)
Solution
C.
At t = 2τ, q = CV (1-e-2)
For charging of capacitor
q = CV (1-e1/τ)
At t = 2τ, q =CV (1-e-2)
