Question
Two capacitors C1 and C2 are charged to 120 V and 200 V respectively. It is found that by connecting them together the potential on each one can be made zero. Then
-
5C1 = 3C2
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3C1 = 5C2
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3C1 = 5C2 = 0
-
9C1 = 4C2
Solution
B.
3C1 = 5C2
q1 = q2
C1V1 = C2V2
120C1 = 200C2
⇒ 3C1 = 5C2
