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Wave Optics

Question
CBSEENPH12039505

Hydrogen (1H1), deuterium (1H2), singly ionised helium (2He4+) and doubly ionised lithium (3Li8)2+ all have one electron around the nucleus. Consider an electron transition from n =2 to n=1. If the wavelengths of emitted radiation are λ123 andλ4, respectively for four elements, then approximately which one of the following is correct?

  •  4λ1=2λ2=2λ3 =λ4

  •  λ1=2λ2=2λ3 =λ4

  •  λ12=4λ3 =9λ4

  •  λ1=2λ2=3λ3 =4λ4

Solution

C.

 λ12=4λ3 =9λ4

For hydrogen atom, we get
1 over straight lambda space equals space Rz squared open parentheses 1 over 1 squared minus 1 over 2 squared close parentheses
1 over straight lambda subscript 1 space equals space straight R space left parenthesis 1 right parenthesis squared open parentheses 3 over 4 close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 2 end style end fraction space equals space straight R space left parenthesis 1 right parenthesis squared open parentheses fraction numerator begin display style 3 end style over denominator begin display style 4 end style end fraction close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 3 end style end fraction space equals space straight R space left parenthesis 2 right parenthesis squared open parentheses fraction numerator begin display style 3 end style over denominator begin display style 4 end style end fraction close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 4 end style end fraction space equals space straight R space left parenthesis 3 right parenthesis squared open parentheses fraction numerator begin display style 3 end style over denominator begin display style 4 end style end fraction close parentheses
fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 1 end style end fraction space equals space fraction numerator begin display style 1 end style over denominator begin display style 4 straight lambda subscript 3 end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style 9 straight lambda subscript 4 end style end fraction space equals fraction numerator begin display style 1 end style over denominator begin display style straight lambda subscript 2 end style end fraction