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Electrostatic Potential And Capacitance

Question
CBSEENPH12039595

A charge Q is placed at each of the opposite corners of a square. A charge q is placed at each of the other tow corners. If the net electrical force on Q is zero, then Q/q equals

  • negative 2 square root of 2
  • 1

  • -1

  • negative fraction numerator 1 over denominator square root of 2 end fraction

Solution

A.

negative 2 square root of 2

Three forces F41, F42 and f43 acting on Q are shown Resultant of F41 + F43
space equals space square root of 2 space straight F subscript each
space equals space square root of 2 space fraction numerator 1 over denominator 4 πε subscript straight o end fraction Qq over straight d squared
Resultant on Q becomes zero only when ‘q’ charges are of negative nature.

straight F subscript 4 comma 2 end subscript space equals space fraction numerator 1 over denominator 4 space πε subscript straight o end fraction fraction numerator straight Q space straight x space straight Q over denominator left parenthesis square root of 2 straight d right parenthesis squared end fraction
rightwards double arrow space square root of 2 dQ over straight d squared space equals space fraction numerator straight Q space xQ over denominator 2 straight d squared end fraction
rightwards double arrow space square root of 2 space straight x space straight q space equals space fraction numerator straight Q space straight x space straight Q over denominator 2 straight d squared end fraction
therefore space straight q space equals space minus fraction numerator straight Q over denominator 2 square root of 2 end fraction space space or space straight Q over straight q space equals space minus 2 square root of 2

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