In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be :

$CE fraction numerator straight r over denominator left parenthesis straight r space plus straight r subscript 2 right parenthesis end fraction$
$CE fraction numerator straight r subscript 1 over denominator left parenthesis straight r space subscript 1 plus straight r right parenthesis end fraction$

CE

CE $fraction numerator straight r subscript 1 over denominator left parenthesis straight r subscript 2 space plus straight r right parenthesis end fraction$

Solution

CE fraction numerator straight r over denominator left parenthesis straight r space plus straight r subscript 2 right parenthesis end fraction

⇒ VAB = VCD

rightwards double arrow space straight V subscript AB space equals space open parentheses fraction numerator straight epsilon over denominator straight r plus space straight r subscript 2 end fraction straight x space straight r subscript 2 close parentheses space minus straight V subscript CD rightwards double arrow space straight Q subscript straight c space equals space CV subscript AB space equals space CE open parentheses fraction numerator straight r subscript 2 over denominator straight r space plus straight r subscript 2 end fraction close parentheses

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