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Wave Optics

Question
CBSEENPH12039572

A diverging lens with the magnitude of focal length 25 cm is placed at a distance of 15 cm from a converging lens of the magnitude of focal length 20 cm. A beam of parallel light falls on the diverging lens. The final image formed is

  • real and at a distance of 40 cm from the divergent lens

  • real and at a distance of 6 cm from the convergent lens

  • real and at a distance of 40 cm from the convergent lens

  • virtual and at a distance of 40 cm from the convergent lens

Solution

C.

real and at a distance of 40 cm from the convergent lens

As parallel beam incident on diverging lens if forms virtual image at v1 = –25 cm from the diverging lens which works as an object for the converging lens (f = 20 cm)

So for converging lens u = -40 cm, f = 20 cm
therefore final image
1 over straight v space minus fraction numerator 1 over denominator negative 40 end fraction space equals space 1 over 20
V = 40 cm from the converging lens.


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