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Electrostatic Potential And Capacitance

Question
CBSEENPH12039565

In a series LCR circuit, R = 200 Ω and the voltage and the frequency of the main supply is 220 V and 50 Hz respectively. On taking out the capacitance from the circuit the current lags behind the voltage by 30º. On taking out the inductor from the circuit the current leads the voltage by 30º. The power dissipated in the LCR circuit is

  • 305 W

  • 210 W

  • zero

  • 242 W

Solution

D.

242 W

The given circuit is under resonance as XL = XC. Hence, power dissipated in the circuit is 
P = V2/R = 242 W

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