Question
A rectangular loop has a sliding connector PQ of length
Solution
C.
A moving conductor is equivalent to a battery of emf
= vBI
Equivalent circuit I = I1 + I2
Applying Kirchhoff's law
I1R + IR -vBl = 0 .... (i)
I2R + IR -vBl = 0 .... (ii)
Adding Eqs. (i) and (ii), we get
2IR + IR = 2vBI
I = 2VBI/3R
I1 = I2 = VBI/3R
