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Electrostatic Potential And Capacitance

Question
CBSEENPH12039549

A current I flows in an infinitely long wire with cross-section in the form of a semicircular ring of radius R. The magnitude of the magnetic induction along its axis is

  • fraction numerator straight mu subscript 0 straight I over denominator 2 πR end fraction

  • fraction numerator straight mu subscript 0 straight I over denominator 2 πR end fraction
  • fraction numerator straight mu subscript 0 straight I over denominator 4 πR end fraction
  • fraction numerator straight mu subscript 0 straight I over denominator straight pi squared straight R end fraction

Solution

D.

fraction numerator straight mu subscript 0 straight I over denominator straight pi squared straight R end fraction straight v equals space straight I over πR
dB space equals space open parentheses fraction numerator straight mu subscript straight o over denominator 4 straight pi end fraction close parentheses fraction numerator 2 straight I over denominator straight R end fraction
straight I space equals space λRdθ
therefore space straight B space equals space integral subscript negative straight pi divided by 2 end subscript superscript straight pi divided by 2 end superscript space dB space cos space straight theta
space equals space fraction numerator straight mu subscript 0 straight lambda over denominator 2 straight pi end fraction integral subscript negative straight pi divided by 2 end subscript superscript straight pi divided by 2 end superscript space cos space θdθ
space equals space fraction numerator straight mu subscript 0 straight lambda over denominator straight pi end fraction space equals space fraction numerator straight mu subscript 0 straight I over denominator straight pi squared straight R end fraction

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