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Nuclei

Question
CBSEENPH12039427

A radioactive isotope has a half-life of 10 years. How long will it take for the activity to reduce to 3.125 %?

Solution

A0  = 100

At = 3.125

At = A0.e-λt

3.125 = 100 e-0.69310t3.125100 = e-0.0693 t1003.125 = e0.0693 tloge 1003.125 = 0.0693 tt2 = 2.303 log10120.0693t = 50.1 years