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Atoms

Question

A hydrogen atom initially in the ground state absorbs a photon which excites it to the n = 4 level. Estimate the frequency of the photon.

Solution

$E_{4} - E_{1} = \frac{hv}{e} \frac{13.6}{4} + 13.6 = \frac{6.63 x 10^{- 34} x v}{1.6 x 10^{- 19}} 13.6 = [1 - \frac{1}{4}] = \frac{6.63 x 10^{- 34}}{1.6 x 10^{- 19}} v \frac{1.6 x 10^{- 19} x 13.6 x 3}{6.63 x 10^{- 34} x 4} = v v = 2.4615 x 10^{15} Hz$

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Atoms

A hydrogen atom initially in the ground state absorbs a photon which excites it to the n = 4 level. Estimate the frequency of the photon.

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Which of the following transitions in hydrogen atoms emit photons of highest frequency?

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