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Wave Optics

Question
CBSEENPH12039421

If one of two identical slits producing interference in Young’s experiment is convered with glass, so that the light intensity passing through it is reduced to 50%, find the ratio of the maximum and minimum intensity of the fringe in the interference pattern.

Solution

As we know that intensity is directly proportional to the square of the amplitude.

I  a2If I1 =I2If intensity reduced to 50%, amplitude will be a2then r = 2thenImaxImin = (r +1)2(r-1)2 = (2+ 1)2(2-1)2ImaxImin = 2.4140.4142 = (5.83)2ImaxImin = 33.98 = 34