Question
A 10 V cell of negligible internal resistance is connected in parallel across a battery of emf 200 V and internal resistance 38 Ω as shown in the figure. Find the value of current in the circuit.
Solution
The positive terminals are connected to the offsite ends of the resistor, they send the current in opposite directions.
Hence, the net emf = 200-10 = 190 V
∴ current in the circuit I = E/R
= 190V / 38 Ω
= 5 A
