Question
In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be
-
8 A
-
10 A
-
12 A
-
14 A
Solution
C.
12 A
Total power (P) consumed
= (15 x 40) + ( 5x 100) + ( 5x 80) + (1 x 1000) = 2500
Power, P = VI
Minimum capacity should be 12 A.
