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Electrostatic Potential And Capacitance

Question
CBSEENPH12039495

A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close to

  • 6 x 10-7 C/m2

  • 3  x 10-7 C/m2

  • 3 x 104 C/m2

  • 6x 104 C/m2

Solution

A.

6 x 10-7 C/m2

When free space between parallel plate capacitor, straight E space equals straight sigma over straight epsilon subscript 0
When dielectric is introduced between parallel plates of capacitor, 
straight E to the power of apostrophe space equals space straight sigma over Kε subscript 0
Electric field inside dielectric 
straight sigma over Kε subscript 0 space equals space 3 space straight x space 10 to the power of 4
where, K = dielectric constant of medium = -2.2
εo = permitivity of free space = 8.85 x 10-12
σ = 2.2 x 8.85 x 10-12 x 3 x 104
 = 6.6 x 8.85 x 10-8 = 5.841 x10-7
 = 6 x 10-7 C/m2

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