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Current Electricity

Question
CBSEENPH12039485
Wired Faculty App

In the circuit shown, the current in the 1Ω resistor is:

  • 1.3 A from P to Q

  • 0 A

  • 0.13 A, from Q to P

  • 0.13 A, from P to Q

Solution

C.

0.13 A, from Q to P

Connect Point Q to ground and by applying Kirchhoff's laws
consider the grounded circuit as shown below,

Applying Kirchhoff's law at point Q,
Incoming current at Q = outgoing current from Q
fraction numerator straight V plus 6 over denominator 3 end fraction space plus straight V over 1 space equals space fraction numerator 9 minus straight V over denominator 5 end fraction or space space straight V open square brackets 1 third plus 1 fifth plus 1 close square brackets space equals space 9 over 5 minus 2 or space straight V space open square brackets fraction numerator begin display style 5 plus 3 plus 15 end style over denominator 15 end fraction close square brackets space equals space fraction numerator 9 minus 10 over denominator 5 end fraction or space straight V space open square brackets 23 over 15 close square brackets space equals space minus space 1 fifth space or space straight V space equals space minus space fraction numerator negative 3 over denominator 23 end fraction space equals space minus space 0.13 space straight V
Thus, current in the 1Ω resistance is 0.13 A, from Q to P

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